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IBM C9050-042 Exam Overview:

IBM C9050-042 Exam Syllabus Topics:

IBM Developing with IBM Enterprise PL/I: Frequently Asked Questions

IBM Developing with IBM Enterprise PL/I Sample Questions:

Question 1

In the following example, what value will be written to SYSPRINT, if anything, by the PUT statement in
PGM_A?
PGM_A: PROC;
DCL INPARM CHAR (12) INIT('FIRST CALL? ');
DCL P_OUT PTR;
DCL OUTPARM CHAR (10) BASED (P_OUT);
DCL PGM_B ENTRY (CHAR(12),PTR) EXTEPNAL;
CALL PGM_B (INPARM,P_OUT);
IF OUTPARM = 'YES' THEN
DO;
INPARM = 'FOLLOW ON';
CALL PGM_B (INPARM,P_OUT);
END;
ELSE
DO;
INPARM = 'NORMAL CALL';
CALL PGM_B (INPARM,P_OUT);
END;
PUT SKIP LIST(OUTPARM);
END;
PGM_B: PROC(INPARM,P_OUT);
DCL INPARM CHAR (12);
DCL P_OUT PTR;
DCL OUTPARM CHAR (12) STATIC INIT(");
P_OUT = ADDR(OUTPARM);
IF INPARM = 'FIRST CALL? ' THEN
OUTPARM = 'YES'; ELSE
IF OUTPARM = " THEN
OUTPARM = 'FIRST CALL';
END;

A. The results are unpredictable.
B. blanks
C. 'YES'
D. 'FIRST CALL'

Question 2

Which code should NOT be split out into separate subroutines?

A. Redundant code in a group otprograms.
B. Code which must be available on different platforms.
C. Redundant code in a program.
D. Dead code in a program.

Question 3

Which of the following best describes an atomic transaction?

A. If one part of the transaction fails, the remainder may still be processed
B. Only valid data will be written to database
C. The database modifications must follow an 'all or nothing' rule
D. Referential Integrity is maintained in the database

Question 4

In a multithreading environment, when can a race condition occur between two threads?

A. When they periorm an operation on same memory area
B. When the threads have the same priority
C. When they cause a deadlock
D. When they operate synchronously

Question 5

Given the following declarations, which is the WORST way of setting D from 5?
DCL 1 S,
2 A(100) CHAR(1),
2 B(100) CHAR(2),
2 C(100) CHAR(3);
S = "; DCL D CHAR(600);
DCLI BIN FIXED(31);

A. CALL PLIOVER(ADDR(D)ADDR(S),600);
B. D = STRING(A) !! STRING(S) !! STRING(C);
C. D = STRING(S);
D. DO I = 1 TO 100;
SUBSTR(D,I,1) = S.A(l);
SUBSTR(D,1 01 + ((I-1) *2),2) = S.B(I);
SUBSTR(D,301 + ((I-1) *3),3) = S.C(I);
END;

Solutions: