Oracle Java SE 8 Programmer II (1z0-809日本語版) follows objectives published by Oracle, so preparation should stay aligned with the official outline. Actual4dump organizes 209 1z0-809日本語 practice questions around those exam areas to support focused review.

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Oracle 1z0-809日本語 Exam Overview:

Oracle 1z0-809日本語 Exam Syllabus Topics:

Oracle 1z0-809日本語 Exam Questions Answered

Oracle Java SE 8 Programmer II (1z0-809日本語版) Sample Questions:

Question 1

コードの断片を考えると：

結果は何ですか？

A. [X、X]
[X、X、X、X]
B. [X]
[X、X]
[X、X、X]
[X、X、X、X]
C. [X]
[X、X]
[X、X、X]
D. [X、X]

Question 2

Given:
Book.java:
public class Book {
private String read(String bname) { return "Read" + bname }
}
EBook.java:
public class EBook extends Book {
public class String read (String url) { return "View" + url }
}
Test.java:
public class Test {
public static void main (String[] args) {
Book b1 = new Book();
b1.read("Java Programing");
Book b2 = new EBook();
b2.read("http://ebook.com/ebook");
}
}
結果は何ですか？

A. The Test.java file fails to compile.
B. Read Java Programming
View http:/ ebook.com/ebook
C. The EBook.java file fails to compile.
D. Read Java Programming
Read http:/ ebook.com/ebook

Question 3

コードの断片を考えると：

結果は何ですか？

A. Java EEJava SE
B. Java EESE
C. Java EEJava EESE
D. The program prints either:
Java EEJava SE
or
Java SEJava EE

Question 4

Given:
public class product {
int id; int price;
public Product (int id, int price) {
this.id = id;
this.price = price;
}
public String toString() { return id + ":" + price; }
}
and the code fragment:
List<Product> products = Arrays.asList(new Product(1, 10),
new Product (2, 30),
new Product (2, 30));
Product p = products.stream().reduce(new Product (4, 0), (p1, p2) -> {
p1.price+=p2.price;
return new Product (p1.id, p1.price);});
products.add(p);
products.stream().parallel()
.reduce((p1, p2) - > p1.price > p2.price ? p1 : p2)
.ifPresent(System.out: :println);
結果は何ですか？

A. 4 : 0
B. 4 : 70
C. The program prints nothing.
D. 4 : 602 : 303 : 201 : 10
E. 2 : 30

Question 5

java.util.stream.Streamについて正しい記述はどれですか？

A. ストリームの実行モードは、処理中に変更できます。
B. ストリームはソースデータを変更するためのものです。
C. ストリームは複数回使用できません。
D. 並列ストリームは、同等の順次ストリームよりも常に高速です。

Solutions: